a: \(=\dfrac{2x^2+x+2x+1-5}{2x+1}=x+1+\dfrac{-5}{2x+1}\)
Để đây là phép chia hết thì \(2x+1\in\left\{1;-1;5;-5\right\}\)
hay \(x\in\left\{0;-1;2;-3\right\}\)
b: \(=\dfrac{3x^3-6x^2+7x^2-14x+14x-28+16}{x-2}=3x^2+7x+14+\dfrac{16}{x-2}\)
Để đây là phép chia hết thì \(x-2\in\left\{1;-1;2;-2;4;-4;8;-8;16;-16\right\}\)
hay \(x\in\left\{3;1;4;0;6;-2;10;-6;18;-14\right\}\)