ĐKXĐ: \(x>3\)
\(\log_2x-\dfrac{1}{2}log_2\left(x-3\right)=2\)
\(\Leftrightarrow2\log_2x-log_2\left(x-3\right)=4\)
\(\Leftrightarrow\log_2\dfrac{x^2}{x-3}=4\)
\(\Leftrightarrow\dfrac{x^2}{x-3}=16\)
\(\Leftrightarrow x^2-16x+48=0\Rightarrow\left[{}\begin{matrix}x=12\\x=4\end{matrix}\right.\)