\(y'=-4x^3+2\left(2m-3\right)x\)
Hàm nghịch biến trên (1;3) khi với mọi \(x\in\left(1;3\right)\) ta có:
\(-4x^3+2\left(2m-3\right)x\le0\)
\(\Leftrightarrow2mx\le2x^3+3x\)
\(\Leftrightarrow m\le x^2+\dfrac{3}{2}\)
\(\Leftrightarrow m\le\min\limits_{\left(1;3\right)}\left(x^2+\dfrac{3}{2}\right)\Rightarrow m\le1+\dfrac{3}{2}=\dfrac{5}{2}\)