Do \(-x^2+2x-5=-\left(x-1\right)^2-4< 0;\forall x\in R\)
Nên BPT tương đương:
\(\dfrac{1}{x^2-mx+1}\ge0\) ; \(\forall x\)
\(\Leftrightarrow x^2-mx+1>0;\forall x\)
\(\Leftrightarrow\left\{{}\begin{matrix}a=1>0\\\Delta=m^2-4< 0\end{matrix}\right.\)
\(\Rightarrow-2< m< 2\)