\(4x=5y\)
\(\Rightarrow\dfrac{x}{5}=\dfrac{y}{4}=\dfrac{2x}{10}=\dfrac{y-2x}{4-10}=\dfrac{-5}{-6}=\dfrac{5}{6}\)
\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{5.5}{6}=\dfrac{25}{6}\\y=\dfrac{5.4}{6}=\dfrac{20}{6}=\dfrac{10}{3}\end{matrix}\right.\)
Ta có: 4x=5y
nên \(\dfrac{x}{\dfrac{1}{4}}=\dfrac{y}{\dfrac{1}{5}}\)
hay \(\dfrac{2x}{\dfrac{1}{2}}=\dfrac{y}{\dfrac{1}{5}}\)
mà 2x-y=5
nên Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:
\(\dfrac{2x}{\dfrac{1}{2}}=\dfrac{y}{\dfrac{1}{5}}=\dfrac{2x-y}{\dfrac{1}{2}-\dfrac{1}{5}}=\dfrac{5}{\dfrac{3}{10}}=\dfrac{50}{3}\)
Suy ra: \(\left\{{}\begin{matrix}x=\dfrac{25}{6}\\y=\dfrac{10}{3}\end{matrix}\right.\)