\(\frac{x^2+4x+4}{x}\left(+\right)=x+4+\frac{4}{x}Ap-dung-bdt-co-si--TA-CO\\ x+\frac{4}{x}\ge2\sqrt{x\cdot\frac{4}{x}}=4=>\left(+\right)\ge4+4=8\\ Dau-"="-xay-ra-tai-x=2\)
\(\frac{x^2+4x+4}{x}\left(+\right)=x+4+\frac{4}{x}Ap-dung-bdt-co-si--TA-CO\\ x+\frac{4}{x}\ge2\sqrt{x\cdot\frac{4}{x}}=4=>\left(+\right)\ge4+4=8\\ Dau-"="-xay-ra-tai-x=2\)
b, \(D=\frac{x^5+2}{x^3}\) Với x > 0
4, (34, 36/ 221) Tìm GTNN của bt: a, E=\(x^2+\frac{2}{x^3}\) với x > 0; b, \(F=\frac{x^3+1}{x^2}\) Với x > 0
6, (68/28 BÙI VĂN TUYÊN) Tìm GTNN của bt: \(Q=\frac{x^2+2x+17}{2\left(x+1\right)}\) Với x > 0
7, (69/28 BÙI VĂN TUYÊN) Tìm GTNN của bt: \(R=\frac{x+6\sqrt{x}+34}{\sqrt{x}+3}\) Với x > 0
8, (70/28 BÙI VĂN TUYÊN) Tìm GTNN của bt: \(S=\frac{x^3+2000}{x}\) Với x > 0
Gpt: a) \(\sqrt[4]{3\left(x+5\right)}-\sqrt[4]{11-x}=\sqrt[4]{13+x}-\sqrt[4]{3\left(3-x\right)}\)
b) \(\frac{1+2\sqrt{x}-x\sqrt{x}}{3-x-\sqrt{2-x}}=2\left(\frac{1+x\sqrt{x}}{1+x}\right)\) c) \(\sqrt{x+1}+\frac{4\left(\sqrt{x+1}+\sqrt{x-2}\right)}{3\left(\sqrt{x-2}+1\right)^2}=3\)
d) \(\sqrt{\frac{x-2}{x+1}}+\frac{x+2}{\left(\sqrt{x+2}+\sqrt{x-2}\right)^2}=1\) e) \(2x+1+x\sqrt{x^2+2}+\left(x+1\right)\sqrt{x^2+2x+2}=0\)
f) \(\sqrt{2x+3}\cdot\sqrt[3]{x+5}=x^2+x-6\)
Tìm GTLN:
\(A=\frac{\sqrt{10x-49}}{2020}\\ B=\frac{\sqrt{2x^2-25}}{2020x^2}\\ C=\frac{7x^8+256}{x^7}\left(x>0\right)\\ D=\frac{\sqrt{x}+6\sqrt{x}+34}{\sqrt{x}+3}\\ E=x+\frac{1}{x-1}\left(x>1\right)\)
Cho bt: \(D=\left(\frac{2\sqrt{x}}{\sqrt{x}+3}+\frac{\sqrt{x}}{\sqrt{x}-3}-\frac{3x+3}{x-9}\right).\left(\frac{2\sqrt{x}-2}{\sqrt{x}-3}-1\right)\)
a. Tìm đKXđ, rút gọn bt
b. Tìm x để D<\(-\frac{1}{2}\)
c. Tìm GTNN của D
Giải phương trình:
\(a)\sqrt{x^2+2x+4}\ge x-2\\ b)x=\sqrt{x-\frac{1}{x}}+\sqrt{x+\frac{1}{x}}\\ c)\sqrt{x+2+3\sqrt{2x-5}}+\sqrt{x-2\sqrt{2x-5}}\\ d)x+y+z+4=2\sqrt{x-2}+4\sqrt{y-3}+6\sqrt{z-5}\\ e)\sqrt{x}+\sqrt{y-1}+\sqrt{z-2}=\frac{1}{2}\left(x+y+z\right)\)
Tìm điều kiện x để các biểu thức sau \(a)\frac{x}{x^2-4}+\sqrt{x-2}\\ b)\frac{\sqrt{x}}{\left|x\right|-1}\\ c)\frac{2}{\left|x\right|+4}+\sqrt{x^2-4}\\ d)\frac{1}{\sqrt{x-2\sqrt{x-1}}}\\ e)\sqrt{x^2-2x}+3\sqrt{4-x^2}\)
gpt : a) \(\frac{5x}{\sqrt{4-x^2}}+\frac{8}{x^2}+\frac{2x}{4-x^2}+\frac{5\sqrt{4-x^2}}{x}+4=0\)
b) \(\frac{2x}{\sqrt{8x^2+25}}+\frac{125}{x^2}-14=0\)
c) \(\left(x^3-3x+2\right)\sqrt{3x-2}-2x^3+6x^2-4x=0\)
d) \(\sqrt{x^2-x+6}+\frac{4}{x-1}=x^2+x\)
Bài 1: Tính :
\(C=\sqrt{\frac{3\sqrt{3}-4}{2\sqrt{3}+1}}-\sqrt{\frac{\sqrt{3}+4}{5-2\sqrt{3}}}\)
\(B=\frac{1}{\sqrt{1}+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+\frac{1}{\sqrt{3}+\sqrt{4}}+....+\frac{1}{\sqrt{99}+\sqrt{100}}\)
\(D=\sqrt{1+\sqrt{3+\sqrt{13+4\sqrt{3}}}}+\sqrt{1-\sqrt{3-\sqrt{13-4\sqrt{3}}}}\)
Bài 2 : Cho \(P=\left(\frac{1}{\sqrt{x}-1}+\frac{x-\sqrt{x}+6}{x+\sqrt{x}-2}\right):\left(\frac{\sqrt{x}+1}{\sqrt{x}+2}+\frac{x-\sqrt{x}-2}{x+\sqrt{x}+2}\right)\)
a, Rút gọn P
b, Tìm GTNN
c, Tìm x để \(P.\frac{x-1}{x^2+8x}< -2\)
P = \(\left(\frac{\sqrt{x}+3}{\sqrt{x}-2}+\frac{\sqrt{x}+2}{3-\sqrt{x}}+\frac{\sqrt{x}+2}{x-5\sqrt{x}+6}\right):\left(1-\frac{\sqrt{x}+1}{x+2\sqrt{x}+1}\right)\)
c) Tìm x để A = \(\frac{1}{P}\) đạt GTNN