Vậy Max A = 15 <=> x = 1
\(-\left(x^2-4\right)^2\le0\Rightarrow B=-2015-\left(x^2-4\right)^2\le-2015\)Vậy Max B = -2015 <=> x = \(\pm2\)
\(A=15-2\left(x-1\right)^2\)
Vì \(-2\left(x-1\right)^2\le0\)
\(\Rightarrow15-2\left(x-1\right)^2\le15\)
Khi \(x-1=0\)
\(x=1\)
Vậy \(GTLN\) của A là 15 khi x = 1
\(B=-2015-\left(x^2-4\right)^2\)
Vì : \(-\left(x^2-4\right)^2\le0\)
\(\Rightarrow-2015-\left(x^2-4\right)^2\le-2015\)
Vậy GTLN của B là -2015 khi x = 2 ; x = -2
a)Ta thấy: \(2\left(x-1\right)^2\ge0\)
\(\Rightarrow-2\left(x-1\right)^2\le0\)
\(\Rightarrow15-2\left(x-1\right)^2\le15-0=15\)
\(\Rightarrow A\le15\)
Dấu = khi x=1
Vậy MaxA=15 khi x=1
a)Ta thấy:\(\left(x^2-4\right)^2\ge0\)
\(\Rightarrow-\left(x^2-4\right)^2\le0\)
\(\Rightarrow-2015-\left(x^2-4\right)^2\le-2015-0=-2015\)
\(\Rightarrow B\le-2015\)
Dấu = khi \(\left[\begin{array}{nghiempt}x=2\\x=-2\end{array}\right.\)
Vậy MaxB=-2015 khi x=2 hoặc -2