\(B=4x^2+4x+1-9x^2+12x-4+x-11\)
\(=-5x^2+17x-14\)
\(=-5\left(x^2-\dfrac{17}{5}x+\dfrac{14}{5}\right)\)
\(=-5\left(x^2-2\cdot x\cdot\dfrac{17}{10}+\dfrac{289}{100}-\dfrac{9}{100}\right)\)
\(=-5\left(x-\dfrac{17}{10}\right)^2+\dfrac{9}{20}\le\dfrac{9}{20}\)
Dấu '=' xảy ra khi x=17/10