a) A = ( 3x - 1)2 - 4/ 3x - 1/ + 5
Dat : 3x - 1 = a , ta co :
A = a2 - 4a + 5
A = a2 - 4a + 4 + 1
A = ( a - 2)2 + 1
A = ( 3x - 3)2 + 1
Do : ( 3x - 3)2 ≥ 0 ∀x
⇒ ( 3x - 3)2 + 1 ≥ 1
⇒ AMIN = 1 ⇔ x = 1
b)
A-3y=2x
x=(A-3y/2)
x^2+y^252<=>A^2+9/4y^2-3Ay+y^2=52
<=>13y^2-12Ay=4.52-4A^2
13y=z
z^2-12z=4.13.52-13.4A^2
(z-6)^2=4.13.52+36-4.13A^2
vT>=0
=>Vp>=0
=>A^2<=(4.13.52+36)/(4.13)=(13.52+9)/13=685/13
A<=√(685/13)