\(B=\left(x-2\right)\left(x-3\right)\left(x-4\right)\left(x-5\right)+6\)
\(B=\left(x-2\right)\left(x-5\right)\left(x-3\right)\left(x-4\right)+6\)
\(B=\left(x^2-7x+10\right)\left(x^2-7x+12\right)+6\)
Đặt \(x^2-7x+11=t\)
\(B=\left(t-1\right)\left(t+1\right)+6=t^2+5\ge5\)