\(-\dfrac{2}{5}< \dfrac{a}{30}< -\dfrac{1}{6}\Leftrightarrow-\dfrac{12}{30}< \dfrac{a}{30}< -\dfrac{5}{30}\\ \Leftrightarrow a\in\left\{-11;-10;-9;-8;-7;-6\right\}\)
Phân số cần tìm \(-\dfrac{11}{30};-\dfrac{1}{3};-\dfrac{3}{10};-\dfrac{4}{15};-\dfrac{7}{30};-\dfrac{1}{5}\)
Gọi tử số là x
Theo đề bài ta có:
\(-\dfrac{2}{5}< \dfrac{x}{30}< -\dfrac{1}{6}\)
\(\Leftrightarrow\dfrac{-12}{30}< \dfrac{x}{30}< -\dfrac{5}{30}\)
\(\Leftrightarrow-12< x< -5\)
Do \(x\in Z\)
\(\Rightarrow x\in\left\{-11;-10;-9;-8;-7;-6\right\}\)
\(\dfrac{-2}{5}=\dfrac{-12}{30}\)
\(\dfrac{-1}{6}=\dfrac{-5}{30}\)
\(\Rightarrow\dfrac{-12}{30}< \dfrac{-11}{30}< \dfrac{-10}{30}...< \dfrac{5}{30}\)
\(\Rightarrow-12< -11< -10< ...< 5\)
\(\Rightarrow\)...