Ta có:|2x-5|=x+2
Do đó:+TH1:2x-5=x+2
2x-x=5+2
x=7
+TH2:2x-5=-(x+2)
2x-5=-x-2
2x-(-x)=5-2
3x=3
x=1
Vậy x=7;x=1
\(ĐKXĐ:2x-5\ge0\Rightarrow x\ge\frac{5}{2}\)
\(\left[\begin{array}{nghiempt}2x-5=x+2\\2x-5=-x-2\end{array}\right.\) =>\(\left[\begin{array}{nghiempt}x=7\\x=1\end{array}\right.\)