Question

thuc hien phep tinh:

a, 1\(\dfrac{1}{2}\).\(2\dfrac{1}{3}\)+1\(\dfrac{1}{3}\).\(\dfrac{1}{2}\)

b, \(\dfrac{1}{9}\).\(\dfrac{2}{145}\)-4\(\dfrac{1}{3}\).2\(\dfrac{2}{145}\)+\(\dfrac{2}{145}\)

Answer 1

Giải:

a) \(1\dfrac{1}{2}.2\dfrac{1}{3}+1\dfrac{1}{3}.\dfrac{1}{2}\)

\(=\dfrac{3}{2}.\dfrac{7}{3}+\dfrac{4}{3}.\dfrac{1}{2}\)

\(=\dfrac{21}{6}+\dfrac{4}{6}\)

\(=\dfrac{1}{6}\left(21+4\right)\)

\(=\dfrac{25}{6}\)

b) \(\dfrac{1}{9}.\dfrac{2}{145}-4\dfrac{1}{3}.2\dfrac{2}{145}+\dfrac{2}{145}\)

\(=\dfrac{1}{9}.\dfrac{2}{145}-\dfrac{13}{3}.\dfrac{292}{145}+\dfrac{2}{145}\)

\(=\dfrac{2}{145}\left(\dfrac{1}{9}-\dfrac{13}{3}.146+1\right)\)

\(=\dfrac{2}{145}\left(-\dfrac{5684}{9}\right)\)

\(=-\dfrac{392}{45}\)

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