Đặt 317=a; 111=b
Theo đề, ta có: \(2\dfrac{1}{a}\cdot\dfrac{3}{b}-\dfrac{a-1}{a}\cdot\dfrac{1}{b}-\dfrac{4}{ab}\)
\(=\dfrac{3\left(2a+1\right)}{ab}-\dfrac{a-1}{ab}-\dfrac{4}{ab}\)
\(=\dfrac{6a+3-a+1-4}{ab}=\dfrac{5a}{ab}=\dfrac{5}{b}=\dfrac{5}{111}\)