\(\sqrt{3+2\sqrt{2}}-\sqrt{6-4\sqrt{2}}=\sqrt{\left(\sqrt{2}\right)^2+2.\sqrt{2}.1+1^2}-\sqrt{2^2-2.2.\sqrt{2}+\left(\sqrt{2}\right)^2}\)
= \(\sqrt{\left(\sqrt{2}+1\right)^2}-\sqrt{\left(2-\sqrt{2}\right)^2}=\sqrt{2}+1-2+\sqrt{2}\)
= \(2\sqrt{2}-1\)