Question

\(\sqrt{2x+1}=2+\sqrt{x-3}\)

Answer 1

ĐKXĐ: \(x\ge3\)

\(\Leftrightarrow2x+1=4+x-3+4\sqrt{x-3}\)

\(\Leftrightarrow x=4\sqrt{x-3}\)

\(\Leftrightarrow x^2=16\left(x-3\right)\)

\(\Leftrightarrow x^2-16x+48=0\Rightarrow\left[{}\begin{matrix}x=12\\x=4\end{matrix}\right.\)