Question

So sánh a/ b và a + 2017/b+2017 với a, b ϵ Z ; b khác 0

Giúp mik với viết cách trình bày ra nha nếu đúng mik tick cho mình đang cần gấp

Answer 1

Ta có:

\(\dfrac{a}{b}=\dfrac{a.\left(b+2017\right)}{b.\left(b+2017\right)}=\dfrac{a.b+a.2017}{b.\left(b+2017\right)}\) (1)

\(\dfrac{a+2017}{b+2017}=\dfrac{b.\left(a+2017\right)}{b.\left(b+2017\right)}=\dfrac{a.b+b.2017}{b.\left(b+2017\right)}\) (2)

Từ (1) và (2) suy ra:

+) Nếu a >b thì \(\dfrac{a.b+a.2017}{b.\left(b+2017\right)}>\dfrac{b.a+b.2017}{b.\left(b+2017\right)}\Rightarrow\dfrac{a}{b}>\dfrac{a+2017}{b+2017}\)

+) Nếu a <b thì \(\dfrac{a.b+a.2017}{b.\left(b+2017\right)}< \dfrac{a.b+b.2017}{b.\left(b+2017\right)}\) \(\Rightarrow\dfrac{a}{b}< \dfrac{a+2017}{b+2017}\)

+) Nếu a =b thì \(\dfrac{a.b+a.2017}{b.\left(b+2017\right)}=\dfrac{b.a+b.2017}{b.\left(b+2017\right)}\Rightarrow\dfrac{a}{b}=\dfrac{a+2017}{b+2017}\)