\(\frac{\frac{5}{5}+\frac{5}{35}-\frac{6}{125}-\frac{6}{2009}-\frac{6}{2011}}{\frac{7}{5}+\frac{7}{35}-\frac{7}{125}-\frac{7}{2009}-\frac{7}{2011}}=\frac{5\left(\frac{1}{5}+\frac{1}{35}-\frac{1}{125}-\frac{1}{2009}-\frac{1}{2011}\right)}{7\left(\frac{1}{5}+\frac{1}{35}-\frac{1}{125}-\frac{1}{2009}-\frac{1}{2011}\right)}=\frac{5}{7}\)
Ta có: \(\sqrt{529}=\sqrt{23^2}=23\)
Thấy: \(\sqrt{37}>\sqrt{36}\); \(\sqrt{50}>\sqrt{49}\); \(\sqrt{101}>\sqrt{100}\)
\(\Rightarrow\sqrt{37}+\sqrt{50}+\sqrt{101}>\sqrt{36}+\sqrt{49}+\sqrt{100}=6+7+10=23\)
Mà \(\sqrt{529}=23\) \(\Rightarrow\sqrt{37}+\sqrt{50}+\sqrt{101}>\sqrt{529}\)