Đặt S = 1+10+102+103+...+102014
10S = 10 + 102 + 103 +.......+ 102015
Ta có : 10S - S = ( 10 + 102 + 103 +.......+102015) - ( 1 +10 + 102 + 103 +........+102014)
9S = 102015 - 1
S = (102015 -1 ) :9
Ta thấy: ( 102015 - 1 ) : 9 < 102015
\(\Rightarrow\) (1+10+102+103+...+102014) < 102015