`x in [-5,5]`
Áp dụng BĐT `|A|-|B|<=|A-B|`
Dấu "=" `AB>=0,|A|>=|B|`
`|x+3|-|3-2x|<=|x+3-3+2x|=3x`
Dấu "=" `(x+3)(3-2x)>=0`
`<=>(x+3)(2x-3)<=0`
`<=>(x+3)(x-2/3)<=0`
`<=>-3<=x<=2/3(1)`
Và `|x+3|>=|3-2x|`
`<=>(x+3)^2>=(3-2x)^2`
`<=>3x(-x+6)>=0`
`<=>x(x-6)<=0`
`<=>0<=x<=6(2)`
`(1)(2)=>0<=x<=2/3`
Mà `x in [-5,5],x in Z`
`=>x=0`