a.
\(=3-2\sqrt{2}-\left(4-\sqrt{8}\right)=-1\)
b.
\(=\frac{2\left(\sqrt{3}+1\right)-2\left(\sqrt{3}-1\right)}{2}=\frac{4}{2}=2\)
a) \(\sqrt{\left(2-1\right)^2}-\left(\sqrt{8}-4\right)\)
=2-1-\(\sqrt{8}\)+4=5-\(\sqrt{8}\)
B)\(\frac{2\sqrt{3}+2-2\sqrt{3}+2}{\sqrt{3^2}-1}\)=\(\frac{4\sqrt{3}+4}{2}\)=2\(\sqrt{3}+4\)