Câu 1:
\(\left(a-b\right)\left(a^2+ab+b^2\right)-\left(a^3+b^3\right)\)
\(=a^3-b^3-a^3-b^3\)
\(=-2b^3\)
Câu 2:
a: \(x^2-6x+9=0\)
\(\Leftrightarrow\left(x-3\right)^2=0\)
=>x-3=0
hay x=3
b: \(x^2-\dfrac{2}{5}x+\dfrac{1}{25}=0\)
\(\Leftrightarrow x^2-2\cdot x\cdot\dfrac{1}{5}+\dfrac{1}{25}=0\)
\(\Leftrightarrow\left(x-\dfrac{1}{5}\right)^2=0\)
=>x-1/5=0
hay x=1/5