Question

Phân tích thành nhân tử

a, 4x^8+1

b, 6x^2+7xy+2y^2

Answer 1

\(6x^2+7xy+2y^2=6x^2+3xy+4xy+2y^2=\left(6x^2+3xy\right)\left(4xy+2y^2\right)=3x\left(2xy+y\right)+2y\left(2x+y\right)=\left(2x+y\right)\left(3x+2y\right)\)

Answer 2

a)

\(4x^8+1\)

\(=\left(4x^8+4x^4+1\right)-4x^4\)

\(=\left(2x^4+1\right)^2-\left(2x^2\right)^2\)

\(=\left(2x^4-2x^2+1\right)\left(2x^4+2x^2+1\right)\)