\(\left(5a-b\right)^2-\left(2a+3b\right)^2=\left(5a-b-2a-3b\right).\left(5a-b+2a+3b\right)=\left(3a-4b\right)\left(6a+2b\right)=2\left(3a-4b\right)\left(3a+b\right)\)
Ta có: \(\left(5a-b\right)^2-\left(2a+3b\right)^2\)
\(=\left(5a-b-2a-3b\right)\left(5a-b+2a+3b\right)\)
\(=\left(3a-4b\right)\left(7a+2b\right)\)
sorry mk làm lỗi 1 chút \(\left(5a-b\right)^2-\left(2a+3b\right)^2=\left(5a-b-2a-3b\right)\left(5a-b+2a+3b\right)=\left(3a-4b\right)\left(7a+2b\right)\)