Question

phân tích đa thức thành nhân tử

a.3x²-11x+6

b.8x²+10x-3

c.8x²-2x-1

d.x²-y²+10x-6y+16

e.x⁴+x²y²+y⁴

Answer 1

a.\(3x^2-11x+6\)

= \(3x^2-9x-2x+6\)

=\(3x\left(x-3\right)-2\left(x-3\right)\)

=\(\left(x-3\right)\left(3x-2\right)\)

b\(8x^2+10x-3\)

=.\(8x^2-2x+12x-3\)

=\(2x\left(4x-1\right)+3\left(4x-1\right)\)

=\(\left(4x-1\right)\left(2x+3\right)\)

d.\(x^2-y^2+10x-6y+16\)

=\(\left(x^2+10x+25\right)-\left(y^2+6y+9\right)\)

=\(\left(x+5\right)^2-\left(y+3\right)^2\)

=\(\left(x+5-y-3\right)\left(x+5+y+3\right)\)

=\(\left(x-y+2\right)\left(x+y+8\right)\)

e.\(x^4+x^2y^2+y^4\)

=\(x^4+2x^2y^2+y^4-x^2+y^2\)

=\(\left(x^2+y^2\right)^2-x^2y^2\)

=\(\left(x^2+y^2-xy\right)\left(x^2+y^2+xy\right)\)

Answer 2

a)

\(=3x^2-9x-2x+6=3x\left(x-3\right)-2\left(x-3\right)=\left(x-3\right)\left(3x-2\right)\)

Answer 3

b)

\(=8x^2-2x+12x-3=2x\left(4x-1\right)+3\left(4x-1\right)=\left(4x-1\right)\left(2x+3\right)\)

Answer 4

c)

\(=8x^2-4x+2x-1=4x\left(2x-1\right)+\left(2x-1\right)=\left(2x-1\right)\left(4x+1\right)\)