Question

Phân tích đa thức thành nhân tử:

a) \(x^2-4y^2-2x+4y\)
b) \(x^2-2xy+y^2-m^2\)

Answer 1

\(a.x^2-4y^2-2x+4y=\left(x^2-2x+1\right)-\left(4y^2-4y+1\right)=\left(x-1\right)^2-\left(2y-1\right)^2=\left(x+2y-2\right)\left(x-2y\right)\)

\(b.x^2-2xy+y^2-m^2=\left(x-y\right)^2-m^2=\left(x-y-m\right)\left(x-y+m\right)\)