a) \(x^3-3x^2+3x-1-y^3=\left(x-1\right)^3-y^3=\left(x-y-1\right)\left[\left(x-1\right)^2+\left(x-1\right)y+y^2\right]\)
\(=\left(x-y-1\right)\left[x^2+2x+1+xy-y+y^2\right]\)
b) \(8x^2+12x-2x-3=4x\left(2x+3\right)-\left(2x+3\right)=\left(2x+3\right)\left(4x-1\right)\)