Question

Phân tích đa thức thành nhân tử ;

a, x³ - 2x² - x cộng 2.

b, 2x² cộng xy - y².

c, x³ - 6x² cộng 16.

Answer 1

b)2x^2+xy-y^2=x^2+xy +x^2-y^2=x(x+y) +(x-y)(x+y) =(x+y)(x+x-y)=(x+y)(2x-y)

Answer 2

a)x^3-2x^2-x+2=x^2(x-2)-(x-2)=(x^2-1)(x-2)=(x-1)(x+1)(x-2)

Answer 3

a. \(x^3-2x^2-x+2=x^2\left(x-2\right)-\left(x-2\right)=\left(x-2\right)\left(x^2-1\right)=\left(x-2\right)\left(x-1\right)\left(x+1\right)\)

Answer 4

b. \(2x^2+xy-y^2=2x^2+2xy-xy-y^2=2x\left(x+y\right)-y\left(x+y\right)=\left(x+y\right)\left(2x-y\right)\)

Answer 5

Câu a :

\(x^3-2x^2-x+2\)

\(=x^2\left(x-2\right)-\left(x-2\right)\)

\(=\left(x-2\right)\left(x^2-1\right)\)

\(=\left(x-2\right)\left(x-1\right)\left(x+1\right)\)

Câu b :

\(2x^2+xy-y^2\)

\(=\left(x^2+xy\right)+\left(x^2-y^2\right)\)

\(=x\left(x+y\right)+\left(x-y\right)\left(x+y\right)\)

\(=\left(x+y\right)\left(2x-y\right)\)

Câu c :

\(x^3-6x^2+16\)

\(=x^3-2x^2-4x^2+8x-8x+16\)

\(=x^2\left(x-2\right)-4x\left(x-2\right)-8\left(x-2\right)\)

\(=\left(x-2\right)\left(x^2-4x-8\right)\)

Wish you study well !!