Question

Phân tích đa thức thành nhân tử

(4a+3b)²-(b-2a)²

Answer 1

\(\left(4a+3b\right)^2-\left(b-2a\right)^2\)

\(=\left(4a+3b-b+2a\right)\left(4a+3b+b-2a\right)\)

\(=\left(6a+2b\right)\left(2a+4b\right)\)

Answer 2

\(\left(4a+3b\right)^2-\left(b-2a\right)^2\)

= \(\left(4a+3b-b+2a\right)\left(4a+3b+b-2a\right)\)

= \(\left(6a+2b\right)\left(4a+4b\right)\)

= \(2\left(3a+b\right).4\left(a+b\right)=8\left(3a+b\right)\left(a+b\right)\)