Question

phân tích đa thức sau thành nhân tử

\(x^3+4x^2+4x+3\)

Answer 1

x³+4x²+4x+3

=x³+3x²+x²+3x+x+3

=(x³+3x²)+(x²+3x)+(x+3)

=x²(x+3)+x(x+3)+(x+3)

=(x+3)(x²+x+1)

Answer 2

\(x^3+4x^2+4x+3\\ =x^3+3x^2+x^2+3x+x+3\\ =x^2\left(x+3\right)+x\left(x+3\right)+\left(x+3\right)\\ =\left(x+3\right)\left(x^2+x+1\right)\)