Lời giải:
ĐK: $x>0; x\neq 4$
a) \(P=\frac{\sqrt{x}-2}{\sqrt{x}(\sqrt{x}-2)}+\frac{2}{\sqrt{x}(\sqrt{x}-2)}=\frac{\sqrt{x}}{\sqrt{x}(\sqrt{x}-2)}=\frac{1}{\sqrt{x}-2}\)
b)
\(x=7+4\sqrt{3}=(2+\sqrt{3})^2\Rightarrow \sqrt{x}=2+\sqrt{3}\)
\(\Rightarrow P=\frac{1}{2+\sqrt{3}-2}=\frac{1}{\sqrt{3}}\)