\(\dfrac{x-3}{x-2}=\dfrac{x-2}{x-4}\)
\(\Leftrightarrow\left(x-3\right)\left(x-4\right)=\left(x-2\right)\left(x-2\right)\)
\(\Leftrightarrow x^2-7x+12=x^2-4x+4\)
\(\Leftrightarrow x^2-7x-x^2+4x=-12+4\)
\(\Leftrightarrow-3x=-8\)
\(\Leftrightarrow x=\dfrac{-8}{-3}=\dfrac{8}{3}\)(Oh....La...La Ngày 8/3)