Gọi đáy là x
Chiều cao là 1/4x
Theo đề, ta có: \(\left(\dfrac{1}{4}x+2\right)\left(x-2\right)=\dfrac{1}{2}\cdot\dfrac{1}{4}x\cdot x+2.5\)
\(\Leftrightarrow\dfrac{1}{4}x^2-\dfrac{1}{2}x+2x-4=\dfrac{1}{8}x^2+2.5\)
\(\Leftrightarrow x^2\cdot\dfrac{1}{8}+\dfrac{3}{2}x-6.5=0\)
hay \(x=-6+2\sqrt{22}\)
=>Chiều cao là \(\dfrac{-3+\sqrt{22}}{2}\left(m\right)\)