L'Hospital:
\(=\lim\limits_{x\rightarrow0}\dfrac{2x\sqrt[7]{1-2x}-\dfrac{2}{7}\left(1-2x\right)^{-\dfrac{6}{7}}\left(x^2+\pi^2\right)-2x}{1}\)
\(=0-\dfrac{2}{7}\pi^2=-\dfrac{2}{7}\pi^2\)
L'Hospital:
\(=\lim\limits_{x\rightarrow0}\dfrac{2x\sqrt[7]{1-2x}-\dfrac{2}{7}\left(1-2x\right)^{-\dfrac{6}{7}}\left(x^2+\pi^2\right)-2x}{1}\)
\(=0-\dfrac{2}{7}\pi^2=-\dfrac{2}{7}\pi^2\)
Tính các giới hạn sau:
Câu 1:
a, limx→\(\pm\)∞ \(\dfrac{\left(2x-3\right)^2\left(4x+7\right)^3}{\left(3x-4\right)^2\left(5x^2-1\right)}\)
b, limx→\(\pm\)∞ \(\dfrac{\sqrt[3]{x^3+2x^2+x}}{2x-2}\)
c, limx→\(\pm\)∞ \(\dfrac{\sqrt[3]{\left(x^3+2x^2\right)^2}+x^3\sqrt{x^3+2x^2}+x^2}{3x^2-2x}\)
d, limx→+∞ \(\dfrac{\left(2-3x\right)^3\left(x+1\right)^2}{1-4x^5}\)
e, limx→+∞ \(\dfrac{\left(2x-3\right)^{20}\left(3x+2\right)^{20}}{\left(2x+1\right)^{50}}\)
g, limx→+∞ \(\dfrac{\left(2x-3\right)^3\left(4x^5+7\right)^9}{11x^{47}-8}\)
Tính giá trị giới hạn lim (x → 0) \(\dfrac{\left(x^2+\Pi^{21}\right)\sqrt[7]{1-2x}-\Pi^{21}}{x}\) là:
Tính giá trị giới hạn \(lim\left(x\rightarrow0\right)\dfrac{\left(x^2+\pi^{21}\right)\sqrt[7]{1-2x}-\pi^{21}}{x}\)
Câu 1:
a, limx→-∞ \(\dfrac{x+\sqrt{x^2+2}}{\sqrt{8x^2+5x+2}}\)
b, limx→-∞ \(\dfrac{\sqrt{x^2+2x}+3x}{\sqrt{4x^2+1}-x+2}\)
c, limx→-∞ \(\dfrac{x+\sqrt{x^2+x}}{3x-\sqrt{x^2+1}}\)
d, limx→-∞ \(\dfrac{\sqrt{x^2+x+2}+3x}{\sqrt{4x^2+1}-x+1}\)
lim x\(\rightarrow o\) \(\dfrac{sin3x}{tan2x}\), lim x\(\rightarrow o\) \(\dfrac{cos\left(x-\dfrac{\pi}{2}\right)}{sin4x}\) , limx\(\rightarrow o\)\(\dfrac{cos\left(\dfrac{\pi}{2}cos2x\right)}{sĩnx^2}\) , lim x\(\rightarrow\)o \(\dfrac{\sqrt{cosx}-1}{xsinx}\)
1/ \(\lim\limits_{x\to 1}\) \(\dfrac{\sqrt[3]{7+x^3}-\sqrt{3+x^2}}{x-1}\)
2/ \(\lim\limits_{x \to \ +\infty} \)\(x\left[\sqrt{4x^2+5}-\sqrt[3]{8x^3-1}\right]\)
3/ \(\lim\limits_{x\to 1}\)\(\dfrac{x^3-2x-1}{x^5-2x-1}\)
Giải giúp mình với ạ
Câu 1:
a, limx→+∞ (\(\sqrt{x+1}-\sqrt{x}\))
b, limx→+∞ (\(\sqrt{x+\sqrt{x}}-\sqrt{x}\))
c, limx→-∞ (\(\sqrt{3x^2+x+1}+x\sqrt{3}\))
d, limx→+∞ (\(\sqrt{x^2+2x+4}-\sqrt{x^2-2x+4}\))
limx→0\(\dfrac{2\sqrt{1+x}-\sqrt[3]{8-x}}{x}\)
Tính các giới hạn sau :
a) \(\lim\limits_{x\rightarrow-3}\dfrac{x+3}{x^2+2x-3}\)
b) \(\lim\limits_{x\rightarrow0}\dfrac{\left(1+x\right)^3-1}{x}\)
c) \(\lim\limits_{x\rightarrow+\infty}\dfrac{x-1}{x^2-1}\)
d) \(\lim\limits_{x\rightarrow5}\dfrac{x-5}{\sqrt{x}-\sqrt{5}}\)
e) \(\lim\limits_{x\rightarrow+\infty}\dfrac{x-5}{\sqrt{x}+\sqrt{5}}\)
f) \(\lim\limits_{x\rightarrow-2}\dfrac{\sqrt{x^2+5}-3}{x+2}\)
g) \(\lim\limits_{x\rightarrow1}\dfrac{\sqrt{x}-1}{\sqrt{x+3}-2}\)
h) \(\lim\limits_{x\rightarrow+\infty}\dfrac{1-2x+3x^3}{x^3-9}\)
i) \(\lim\limits_{x\rightarrow0}\dfrac{1}{x^2}\left(\dfrac{1}{x^2+1}-1\right)\)
j) \(\lim\limits_{x\rightarrow-\infty}\dfrac{\left(x^2-1\right)\left(1-2x\right)^5}{x^7+x+3}\)