Question

\(\lim\limits_{x\rightarrow3^-}\sqrt{x^2+8x+3}\)

Answer 1

\(\lim\limits_{x\rightarrow3^-}\sqrt{x^2+8x+3}\)

\(=\sqrt{\left(-3\right)^2+8\cdot\left(-3\right)^2+3}\)

\(=\sqrt{9+8\cdot9+3}=\sqrt{12+72}=\sqrt{84}=2\sqrt{21}\)

Answer 2

\(\lim\limits_{x\rightarrow3^-}\sqrt{x^2+8x+3}=\sqrt{3^2+8.3+3}=6\)