Question

\(\left(x-3\right)^{x+2}-\left(x-3\right)^{x+8}=0\)

Answer 1

\(\left(x-3\right)^{x+2}-\left(x-3\right)^{x+2}.\left(x-3\right)^6=0\\ \left(x-3\right)^{x+2}\left[1-\left(x-3\right)^6\right]=0\\ \left[{}\begin{matrix}\left(x-3\right)^{x+2}=0\\1-\left(x-3\right)^6=0\end{matrix}\right.=>\left[{}\begin{matrix}x-3=0\\x-3=1\end{matrix}\right.=>x=3;x=4\)

Answer 2

`-> (x-3)^(x+2) . (1 - (x-3)^6) = 0`

`-> (x-3)^(x+2) = 0`

`-> x - 3 = 0`

`-> x = 3`

Answer 3

<=>1=(x-3)⁶

<=>x-3=1 hoặc x-3=-1

=>x=4 hoặc x=2