\(\left|\dfrac{1}{2}.x-3\right|=\left|\dfrac{1}{3}.x-2\right|\Rightarrow\left[{}\begin{matrix}\dfrac{x}{2}-3=\dfrac{x}{3}-2\\\dfrac{x}{2}-3=2-\dfrac{x}{3}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}\dfrac{x}{2}-\dfrac{x}{3}=-2+3\\\dfrac{x}{2}+\dfrac{x}{3}=2+3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}\dfrac{x}{6}=1\\\dfrac{5x}{6}=5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=6\\x=6\end{matrix}\right.\Rightarrow x=6\)
Vậy x=6