\(\Leftrightarrow\left\{{}\begin{matrix}x^2+1=-y^2+4y-xy\\y\left(x+y\right)^2-7y=2\left(x^2+1\right)\end{matrix}\right.\)
Thế trên xuống dưới:
\(y\left(x+y\right)^2-7y=2\left(-y^2+4y-xy\right)\)
\(\Leftrightarrow y\left[\left(x+y\right)^2+2\left(x+y\right)-15\right]=0\)
\(\Leftrightarrow\left[{}\begin{matrix}y=0\left(l\right)\\x+y=3\\x+y=-5\end{matrix}\right.\)