\(\left\{{}\begin{matrix}3x-y=5\\2x+3y=7\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}9x-3y=15\\2x+3y=7\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}11x=22\\3x-y=5\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=2\\6-y=5\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=1\end{matrix}\right.\)
Vậy...
3x-y=5=> 3x-5=y
2x+3y=7
<=> 2x+3(3x-5) =7
<=>2x+9x-15=7
<=> 11x=22=>x=2
Thay x=2 vào biểu thức y=3x-5 ta có:
y=3.2-5=1