Ta có: \(\left(-12\right)^2.x=56+10.13.x\)
\(\Rightarrow144.x=56+130.x\)
\(\Rightarrow144x-56-130x=0\)
\(\Rightarrow144x-130x-56=0\)
\(\Rightarrow14x-56=0\)
\(\Rightarrow14x=56\)
\(\Rightarrow x=\frac{56}{14}=4\)
Vậy: \(x=4\)
Tìm x:
a)\(2016x+\left(\dfrac{7}{12}+\dfrac{4}{21}+\dfrac{2}{24}+\dfrac{11}{30}+\dfrac{3}{40}+\dfrac{15}{56}\right)-\left(\dfrac{2}{3}+\dfrac{2}{4}+\dfrac{2}{5}\right)=0\)
b\(\dfrac{2x-1}{x+2015}-\dfrac{4025}{x+2017}=\dfrac{x-2014}{2x-4036}-\dfrac{x-2013}{2x-4030}\) (x thuộc N)
c)\(\left(1+\dfrac{1}{1.3}\right)\left(1+\dfrac{1}{2.4}\right)\left(1+\dfrac{1}{3.5}\right)...\left(1+\dfrac{1}{x\left(x+2\right)}\right)=\dfrac{4016}{2007}\)
AI GIÚP MK VỚI MK TICK CHO 
Tìm x, biết :
a) \(\left(\dfrac{31}{20}-\dfrac{26}{45}\right).\dfrac{-36}{35}< x< \left(\dfrac{51}{56}+\dfrac{8}{21}+\dfrac{1}{3}\right).\dfrac{8}{13}\)
b) \(\dfrac{-3}{5}.x=\dfrac{1}{4}+0,75\)
c) \(\left(\dfrac{1}{7}-\dfrac{1}{3}\right).x=\dfrac{28}{3}.\left(\dfrac{1}{4}-\dfrac{1}{7}\right)\)
d) \(\dfrac{5}{7}.x=\dfrac{9}{8}-0,125\)
e)\(\left(\dfrac{2}{11}+\dfrac{1}{3}\right).x=\left(\dfrac{1}{7}-\dfrac{1}{8}\right).56\)
Tìm x;y biết
\(x+\left(-\frac{31}{12}\right)^2\left(\frac{49}{12}\right)^2-x=y\)
Tìm x : \(\frac{2}{42}+\frac{2}{56}+\frac{2}{72}+...+\frac{2}{x\cdot\left(x+1\right)}\) =\(\frac{2}{9}\) (x thuộc N*)
Tìm GTLN hoặc GTNN của :
a) \(A=\left|-x+8\right|-21\)
b) \(B=\left|-x-17\right|+\left|y-36\right|+12\)
c) \(C=-\left|2x-8\right|-35\)
d) \(D=3\left(3x-12\right)^2-37\)
e) \(E=-21-3\left|2x+50\right|\)
g) \(G=\left(x-3\right)^2+\left|x^2-9\right|+25\)
tìm x thuộc n biết
a) \(\left(x+2\right)^5=2^{10}\)
b) \(5^x:5^2=125\)
c) \(\left(x+1\right)^2=\left(x+1\right)^0\)
d)\(\left(2+x\right)+\left(4+x\right)+\left(6+x\right)+...+\left(52+x\right)=780\)
e)\(70⋮x,80⋮x\) và x>8
f)\(x⋮12,x⋮25,x⋮30\)và 0<x<500
\(\left(\frac{5}{3}-x\right).\left(\frac{-12}{5}+\frac{3}{2}\right)=-12\frac{1}{2}\)
Tìm GTLN hoặc GTNN của :
a) \(D=3\left(3x-12\right)^2-37\)
b) \(G=\left(x-3\right)^2+\left|x^2-9\right|+25\)
tìm x:
a)\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
b) \(\left(x.6\dfrac{2}{7}+\dfrac{3}{7}\right).2\dfrac{1}{5}-\dfrac{3}{7}=-2\)
c) \(x.3\dfrac{1}{4}+\left(\dfrac{-7}{6}\right).x-1\dfrac{2}{3}=\dfrac{5}{12}\)
d) \(5\dfrac{8}{17}:x+\left(-\dfrac{4}{17}\right):x+3\dfrac{1}{7}:17\dfrac{1}{3}=\dfrac{4}{11}\)
