Cho hình vẽ: Biết Ax // By

Tim x,y:

|x-4|+3|3x-2|-2|2-x|=x+1

||2x-3|-3/4|=5/6

|1/2-|3-x||=2x-1

|x-2007|+2004|y-2008|\(\le\)0

3|x-2y|+4|y+1/2|=0

Cho A=\(4+4^2+4^3+.....+4^{120}\\ CMR:A⋮5;A⋮105\)

Tìm x biết:

\(1+\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{10}+.....+\dfrac{1}{x\left(x+1\right):2}=1\dfrac{1999}{1993}\)

Bạn có phải là Trịnh Thị Mỹ Linh ko vậy?

Ta có

\(27^{11}=\left(3^3\right)^{11}\\ 81^8=\left(3^4\right)^8\\ \)

suy ra \(27^{11}=3^{33}\\ 81^8=3^{32}\\ \)

suy ra\(3^{33}>3^{32}\\ 27^{11}>81^8\)

Tìm x:

a)\(2016x+\left(\dfrac{7}{12}+\dfrac{4}{21}+\dfrac{2}{24}+\dfrac{11}{30}+\dfrac{3}{40}+\dfrac{15}{56}\right)-\left(\dfrac{2}{3}+\dfrac{2}{4}+\dfrac{2}{5}\right)=0\)

b\(\dfrac{2x-1}{x+2015}-\dfrac{4025}{x+2017}=\dfrac{x-2014}{2x-4036}-\dfrac{x-2013}{2x-4030}\) (x thuộc N)

c)\(\left(1+\dfrac{1}{1.3}\right)\left(1+\dfrac{1}{2.4}\right)\left(1+\dfrac{1}{3.5}\right)...\left(1+\dfrac{1}{x\left(x+2\right)}\right)=\dfrac{4016}{2007}\)

AI GIÚP MK VỚI MK TICK CHO

cho mk sửa lại

tacó:

\(\dfrac{-64}{125}=\left(\dfrac{-4}{5}\right)^3\)

suy ra\(\dfrac{2}{3}-\dfrac{3}{5}x=\dfrac{-4}{5}\)

\(\dfrac{3}{5}x=\dfrac{2}{3}-\dfrac{-4}{5}\)

\(\dfrac{3}{5}x=\dfrac{22}{15}\)

\(x=\dfrac{22}{15}:\dfrac{3}{5}\)

\(x=\dfrac{22}{9}\)