- Đây là hóa mà .
PTHH : \(CH_4+2O_2\rightarrow CO_2+2H_2O\)
\(m_{CH_4}=75\%m_{gas}=75\%.33,6=25,2\) ( lít )
\(n_{CH_4}=\frac{V_{CH_4}}{22,4}=\frac{25,2}{22,4}=1,125\left(mol\right)\)
- Theo PTHH : \(n_{O_2}=2n_{CH_4}=2.1,125=2,25\left(mol\right)\)
-> \(V_{O_2}=n_{O_2}.22,4=50,4\left(l\right)\)
Mà \(V_{KK}=5V_{O_2}\)
=> \(V_{KK}=5.50,4=252\left(l\right)\)