MA=0.552*29=16.008=16
nA=11.2/22.4=0.5 (mol)
mA=0.5*16=8(g)
mC=75%*8/100%=6(g)
nC=6/12=0.5(mol)
mH=25%*8/100%=2(g)
nH=2/1=2(mol)
A có ct: CxHy
x/y=0.5/2=1/4
vậy x=1, y=4
Vậy A là CH4
CH4+2O2→CO2+2H2O
mol 0.5---1
nO2=1 mol
VO2=1*22.4=22.4 (l)