Chương I - Căn bậc hai. Căn bậc ba
Các câu hỏi tương tự
I Giải PT
\(\sqrt{x+2+3\sqrt{2x-5}}+\sqrt{x-2-\sqrt{2x-5}}=2\sqrt{2}\)
help me !!!
giải pt \(\sqrt{x+2-3\sqrt{2x-5}}+\sqrt{x-2+\sqrt{2x-5}}=2\sqrt{2}\)
Giải pt:
a) \(\sqrt{2x^2-3}\)=\(\sqrt{4x-3}\)
b) \(\sqrt{2x-1}\)=\(\sqrt{x-1}\)
c) \(\sqrt{x^2-x-6}\)=\(\sqrt{x-3}\)
d) \(\sqrt{x^2-x}\)=\(\sqrt{3x-5}\)
Giúp em với, anh thịnh giúp em xíu á
giải pt: \(\sqrt{x+2-3\sqrt{2x-5}}+\sqrt{x-2+\sqrt{2x-5}}=2\sqrt{2}\)
Thank you so much!!
Bài 1: Tính
a) sqrt{9-sqrt{17}}cdotsqrt{9+sqrt{17}}
b) sqrt{4-sqrt{7}}-sqrt{4+sqrt{7}}
c) left(sqrt{3-sqrt{5}}+sqrt{3+sqrt{5}}right)^2
d) sqrt{2+sqrt{3}}cdotsqrt{2+sqrt{2+sqrt{2+sqrt{3}}}}cdotsqrt{2-sqrt{2+sqrt{2+sqrt{3}}}}
e) sqrt{frac{8+sqrt{15}}{2}}+sqrt{frac{8-sqrt{15}}{2}}
Bài 2: Giải pt:
a) sqrt{x+3-4sqrt{x-1}}+sqrt{x+8-6sqrt{x-1}}1
b) sqrt{x+sqrt{x-11}}+sqrt{x-sqrt{x-11}}4
c) sqrt{x+2+3sqrt{2x-5}}+sqrt{x-2-sqrt{2x-5}}2sqrt{2}
d) sqrt{x-4}+sqrt{6-x}x^2-10x+27
e) sqrt{2x+1}+sqrt{...
Đọc tiếp
Bài 1: Tính
a) \(\sqrt{9-\sqrt{17}}\cdot\sqrt{9+\sqrt{17}}\)
b) \(\sqrt{4-\sqrt{7}}-\sqrt{4+\sqrt{7}}\)
c) \(\left(\sqrt{3-\sqrt{5}}+\sqrt{3+\sqrt{5}}\right)^2\)
d) \(\sqrt{2+\sqrt{3}}\cdot\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{3}}}}\cdot\sqrt{2-\sqrt{2+\sqrt{2+\sqrt{3}}}}\)
e) \(\sqrt{\frac{8+\sqrt{15}}{2}}+\sqrt{\frac{8-\sqrt{15}}{2}}\)
Bài 2: Giải pt:
a) \(\sqrt{x+3-4\sqrt{x-1}}+\sqrt{x+8-6\sqrt{x-1}}=1\)
b) \(\sqrt{x+\sqrt{x-11}}+\sqrt{x-\sqrt{x-11}}=4\)
c) \(\sqrt{x+2+3\sqrt{2x-5}}+\sqrt{x-2-\sqrt{2x-5}}=2\sqrt{2}\)
d) \(\sqrt{x-4}+\sqrt{6-x}=x^2-10x+27\)
e) \(\sqrt{2x+1}+\sqrt{17-2x}=x^4-8x^3+17x^2-8x+22\)
f) \(\sqrt{x+x^2}+\sqrt{x-x^2}=x+1\)
g) \(\sqrt{3x^2+12x+16}+\sqrt{y^2-4y+13}=5\)
Bài 3: Cho biểu thức:
P= \(\frac{\sqrt{x+4\sqrt{x-4}}+\sqrt{x-4\sqrt{x-4}}}{\sqrt{\frac{16}{x^2}-\frac{8}{x}+1}}\)
a) Rút gon P
b) Tìm x để P đạt GTNN, tìm GTNN đó.
c) Tìm x \(\in\) Z để P \(\in\) Z
@Nguyễn Văn Đạt@Akai Haruma Help me please~~~~ Giải thích cẩn thân hộ với.
giải pt sau
1, \(\sqrt{5-2x}=6\)
2,\(\sqrt{2-x}-\sqrt{x+1}=0\)
3, \(\sqrt{4x^2+4x+1}=6\)
4,\(\sqrt{x^2-10x+25}=x-2\)
Giải pt : a) \(\sqrt{3x^2-5x+1}-\sqrt{x^2-2}=\sqrt{3\left(x^2-x-1\right)}-\sqrt{x^2-3x+4}\)
b) \(\left(x-1\right)\sqrt{x^2+5}+x=x^2+1\)
c)\(\sqrt{x+2}+2x-10=\sqrt{2x-3}\)
d)\(\sqrt{2x-3}-\sqrt{x}=2x-6\)
e) \(\sqrt{4x^2+5x+1}-2\sqrt{x^2-x+1}=9x-3\)
\(\sqrt{25t^2-9}=2\sqrt{5t-3}\)
\(\sqrt{-2x^2+6}=x-1\)
help me
giải pt
a>\(\sqrt{2x+3}+\sqrt{5-8x}=\sqrt{4x+7}\)
b>\(\sqrt[3]{x-17}+\sqrt{x+8}=5\)
c>\(\sqrt[3]{4x-y^2}-\sqrt[3]{2+x}=\sqrt[3]{4x^2}\)