a)\(Zn+2HCl--.ZnCl2+H2\)
b)\(m_{HCl}=\frac{14,6.7,3}{100}=1,0658\left(g\right)\)
\(n_{HCl}=\frac{1,0658}{36,5}=0,0292\left(mol\right)\)
\(n_{H2}=\frac{1}{2}n_{HCl}=0,0164\left(mol\right)\)
\(V_{H2}=0,0164.22,4=0,32704\left(l\right)\)
c) \(H2+CuO--->Cu+H2O\)
\(n_{CuO}=\frac{8}{80}=0,1\left(mol\right)\)
=> CuO dư
\(n_{Cu}=n_{H2}=0,0164\left(mol\right)\)
\(m_{C_{ }u}=0,0164.64=1,0496\left(g\right)\)