\(n_{Zn}=\frac{6,5}{65}=0,1\left(mol\right)\)
\(PTHH:Zn+2HCl\rightarrow ZnCl_2+H_2\uparrow\)
\(\left(mol\right)\)___0,1____0,2______0,1_____0,1
\(m_{ZnCl_2}=0,1.136=13,6\left(g\right)\)
\(m_{H_2}=0,1.2=0,2\left(g\right)\)
\(m_{ddZnCl_2}=m_{Zn}+m_{ddHCl}-m_{H_2}=6,5+200-0,2=206,3\left(g\right)\)
\(C\%_{ZnCl_2}=\frac{13,6}{206,3}.100\%=6,6\%\)