Ta có:
\(\dfrac{1}{4}+\dfrac{8}{9}=\dfrac{41}{36}\)
\(1-\left(\dfrac{3}{8}-\dfrac{5}{6}\right)=\dfrac{35}{24}\)
ta lại có:
\(\dfrac{41}{36}=\dfrac{82}{72}\)
\(\dfrac{35}{24}=\dfrac{105}{72}\)
\(\Rightarrow\)82 \(\le\)2x < 105
\(\Rightarrow\)41\(\le\)x<52.5
Vậy 41\(\le\)x<52.5