Question

Giúp tớ với ạ

Answer 1

Ta có :

\(x^3-xy^2+x^2y-y^3-1\)=\(\left(x^3+x^2y\right)-\left(xy^2+y^3\right)-1\)

=\(x^2\left(x+y\right)-y^2\left(x+y\right)-1=x^2.0-y^2.0-1=0-1=-1\)

tick mik nha !!

Answer 2

x³ - xy² + x²y - y³ - 1

= x(x² - y²) + y(x² - y²) - 1

= x(x - y)(x + y) + y(x - y)(x + y) - 1

= (x+y)(x - y)(x + y) - 1

= (x + y)²(x - y) - 1

= 0 - 1

= - 1

Answer 3

-1

Answer 4

-1

Answer 5

-1