Question

giúp em làm vs ạ

Answer 1

a) \(\left(2x-1\right)\left(x^2-x+1\right)+x^2\left(3-2x\right)=2\)

\(\Rightarrow2x^3-2x^2+2x-x^2+x-1+3x^2-2x^3=2\)

\(\Rightarrow\left(2x^3-2x^3\right)-\left(2x^2+x^2-3x^2\right)+\left(2x+x\right)-1=2\)

\(\Rightarrow3x-1=2\)

\(\Rightarrow3x=2-1\)

\(\Rightarrow3x=1\)

\(\Rightarrow x=\dfrac{1}{3}\)

 

Answer 2

a. bằng 1/3 nha

Answer 3

b: =>\(3\left(x-2-4x^2+8x\right)+4\left(3x^2+7x+2\right)=24\)

=>-12x^2+27x-6+12x^2+28x+8=24

=>55x+2=24

=>55x=22

=>x=2/5

c: \(\Leftrightarrow\left(x^2+3x+2\right)\left(x+3\right)-x^3-8x^2-16x-6=0\)

=>\(x^3+6x^2+11x+6-x^3-8x^2-16x-6=0\)

=>\(-2x^2-5x=0\)

=>x=0 hoặc x=-5/2

d: \(\Leftrightarrow x^3+2x^2+4x+x^2+2x+4-x^3-3x^2+8=0\)

=>6x+12=0

=>x=-2