Question

Giải PT : \(x^2-5x+6>0\)

Answer 1

\(x^2-5x+6>0\Leftrightarrow\left(x-2\right)\left(x-3\right)>0\)

Chia 2 trường hợp:

+) T/h 1:

\(\left\{{}\begin{matrix}x-2>0\\x-3>0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x>2\\x>3\end{matrix}\right.\Leftrightarrow x>3\)

+) T/h 2:

\(\left\{{}\begin{matrix}x-2< 0\\x-3< 0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x< 2\\x< 3\end{matrix}\right.\Leftrightarrow x< 2\)

Vậy .................